simpler way?
Blitz3D Forums/Blitz3D Beginners Area/simpler way?
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| Is there a shorter, simpler way to write this? IF (x=0) OR (y=0) OR (z=0) = TRUE THEN blah,blah,blah Thanks |
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| If x*y*z = 0 Then Bla, Bla, Bla... |
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| Nope, that would be IF (x=0) AND (y=0) AND (z=0) = TRUE THEN blah,blah,blah |
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| Actually, Peer was right. x*y*z = 0 if any of x, y or z are 0, so that's an OR. |
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| if x+y+z<3 |
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| That doesn't work. That would return true more than 50% of the time using random integers. For example x=10, y=14, z=-38 |
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| Actually, Peer was right. x*y*z = 0 if any of x, y or z are 0, so that's an OR. Oh, I had an exceptionally stupid moment...! Um.. to do the and, I guess you'd use ORs? if x OR y OR z =0 = if (x=0) and (y=0) and (z=0) |
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| Thanks guys, it looks like Anthony's last one is the one I want. I guess I didn't think to say that there's a 50% chance one, or all three, of the integers could be negative. So it has to work with frequent, multiple negative numbers. And it's so hard to work with numbers that are frequently negative, they always try to bring you down :) |
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| PLease note - my last eg was for AND (even though I used ORs to achieve the ANDy effect) - um, I think... Okay, I checked, and yup, it works, providing you use brackets IF (X OR Y OR Z)=0 THEN... is the same as IF (X=0) AND (Y=0) AND (z=0) otherwise, without the brackets, it's read as IF (x=1) OR (y=1) OR (z=0) THEN... Note though - like the other eg, this is only good for checking against zero... |
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| I'm confused! What I need to know is if ANY of the numbers equals zero. Could be one, could be two, or it could be all three. As long as any one of them equals zero I want the other code to be executed. Does this do that? Your explanation looks like it's contrary to your code. I'm getting really confused. 8) Thanks for trying everyone :) |
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| Your original method didn't need the "= True", so... IF (x=0) OR (y=0) OR (z=0) Then do something. Edit: I was going to say the first reply was also correct: If x*y*z = 0 Then ... Both of them test whether at least one of x,y,z is zero. But in the computer world of only finitely many integers this can fail. Consider: x = 1024 y = 2048 z = 2048 Print x * y * z ; oops So stick with the first method. |
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| Thanks Floyd, at least it trims a tiny bit off. That's still better than nothing. |
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| Seems like a lot of effort to eliminate very little code bloat. Just my opinion. |
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| Seriously. This smacks of something I've been told and have experienced; your optimizing efforts are better spent figuring out better ways of accomplishing tasks (eg. a faster shadow casting algorithm) than nitpicking text. Plus, for a game if you find yourself trying to optimize your "if" statements you ought to be looking to reduce your polygon count are color depth or something; the graphics load has a MUCH bigger influence on performance than the wordiness of your code. |
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| bigger influence on performance than the wordiness of your code. Yup we have no way of knowing how the variations are handled at compile time. All examples shown could result in the exact same code when compiled... |
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| I was assuming this was all in aid of speeding up typing... |
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| I was assuming it was just a simple exercise provided as diversion. |
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| Help, my brain is bleeding... |
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| Actually, it was just an excercise in keeping the code manageable and neat. Purely for my own needs to read it later. Thanks for all the good points that were made. "The mastery comes not from memorizing the information, but from understanding the application of it"...me :) Since I'm still a fledgling programmer everything I understand now will shape how I learn the next thing. So thanks :) |
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| Manageable and neat are subjective, but I can't imagine anyone finding any of the alternatives more readable than: IF (x=0) OR (y=0) OR (z=0) |
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