requestfile parse path

hub	(Posted 2010) [#1]

Hi !
how to parse the result returned by requestfile to have only the file path ?
Thanks !

Czar Flavius

(Posted 2010) [#2]

I don't understand what you mean.

Print RequestFile("")

Picking a random file

C:\BlitzMax\bin\makedocs.exe

To get only the file name, try

Local path:String[] = RequestFile("").Split("\")

Local name:String = path[path.Length-1]

Print name

hub	(Posted 2010) [#3]

i'm searching to get only the path without the file name.

Czar Flavius

(Posted 2010) [#4]

Local path:String = RequestFile("")
Local result:String = path[..path.FindLast("\")]
Print result

Also consider RequestDir

hub	(Posted 2010) [#5]

Many thanks !

Volker

(Posted 2010) [#6]

Or
ExtractDir(requestfile())